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# Return Results from context.run

Always return step results if needed in subsequent steps.

<CodeGroup>

```typescript ❌ Incorrect - TypeScript
export const { POST } = serve<string>(async (context) => {
  const input = context.requestPayload

  let result

  await context.run("step-1", async () => {
    result = await someWork(input)
  })
  await context.run("step-2", async () => {
    await someOtherWork(result)
  })
})
```

```typescript ✅ Correct - TypeScript
export const { POST } = serve<string>(async (context) => {
  const input = context.requestPayload

  const result = await context.run("step-1", async () => {
    return await someWork(input)
  })

  await context.run("step-2", async () => {
    someOtherWork(result)
  })
})
```

```python ❌ Incorrect - Python
@serve.post("/api/example")
async def example(context: AsyncWorkflowContext[str]) -> None:
    input = context.request_payload

    result = None

    async def _step_1() -> Dict:
        nonlocal result
        result = await some_work(input)

    await context.run("step-1", _step_1)

    async def _step_2() -> None:
        await some_other_work(result)

    await context.run("step-2", _step_2)

```

```python ✅ Correct - Python
@serve.post("/api/example")
async def example(context: AsyncWorkflowContext[str]) -> None:
    input = context.request_payload

    async def _step_1() -> Dict:
        return await some_work(input)

    result = await context.run("step-1", _step_1)

    async def _step_2() -> None:
        await some_other_work(result)

    await context.run("step-2", _step_2)

```

</CodeGroup>

Because your workflow endpoint is called multiple times, `result` will be uninitialized when the endpoint is called again to run `step-2`.

If you are curious about why an endpoint is called multiple times, see [how Workflow works](/workflow/basics/how).